IMPORTANT FORMULAs of NCERT CHEMISTRY CLASS 12
UNIT 1: SOLID STATE
1. Density of the unit cell,
d = ZM/a3NA
Where,
Z = No. of atoms per unit cell
M = Molar
Mass/Atomic Mass
a = Edge
Length of unit cell
NA
= Avogadro Constant
2. Efficiency
of Packing in hcp and ccp structures = 74%
It means 74%
of the available volume is occupied by spheres (atoms).
(Note: In
FCC unit cell the atoms touch each other along the face diagonal)
Face diagonal, 4r = √2a ----------- (i)
a = 4r/√2----------
(ii)
r = a/2√2--------
(iii)
where, r = radius of the atom and a = edge
length of unit cell.
3. Efficiency of Packing in bcc structures =
68%
It means 68%
of the available volume is occupied by spheres (atoms).
(Note: In
BCC unit cell the atoms touch each other along the body diagonal)
Body diagonal, 4r = √3a ------------ (i)
a =
4r/√3----------- (ii)
r = √3a/4 ---------- (iii)
4. Packing efficiency in
simple cubic lattice = 52.4%
It means
52.4% of the available volume is occupied by spheres (atoms).
(Note: In
SCC unit cell the atoms touch each other along the edge)
a and r is related as:
a = 2r ---------- (i)
r = a/√2 ---------- (ii)
5. Relationship between
the nearest neighbours distance of an element (d) with edge length(a) of the
unit cell and radius of the atom (r) :
i) In simple cubic element: d
= a = 2r, r = a/2
ii) In bcc element: d = 4r = √3, r = √3a/4
iii) In fcc element: d = 4r = √2a, r = a/2√2
where, d = distance between nearest neighbours.
1. Mass %
=
(Mass of solute/Mass of solution) x 100
2. Volume
% = (Volume of
solute/Volume of solution) x 100
3. ppm
(A) = (Mass of component
A/Total mass of solution) x 106
4. Molarity
(M) = No. of moles of solute / Volume of
Solution (in L)
= nB
/ V (in L) = (wB x 1000)/(mB x V {in
mL})
Here, nB is the no. of
moles of Solute and wB is the given mass of solute.
5. Molarity
equation (Dilution formula): M1V1 = M2V2
6. Molarity
of a mixture: Mmixture
= (M1V1 + M2V2)/(V1 + V2)
7. Molarity
(M) = (10 x X x d)/Molecular mass of solute
where, X =
mass%, d =
density of solution
8. Molality
(m) = No. of moles of
solute / Weight of Solvent (in Kg)
= nB /wA
(in Kg) = (nB x 1000)/wA (in g) = (wB
x 1000)/(mB x wA{in g})
Here, nB is the no. of moles
of Solute, wB is the given
mass of Solute and wA is the given mass of Solvent
9. Mole
fraction (X):
XA = nA/(nA
+ nB); XB = nB/(nA
+ nB)
{Note: XA + XB = 1)
nA & nB
are the no. of moles of component A & B respectively
10. Henry’s
Law:
The partial pressure of the gas in vapour phase (P) is proportional to the mole
fraction of the gas (X) in the solution.
P = kHX
where, kH =
Henry’s Law constant.
11.
Raoult’s Law: i) For a solution of volatile
liquids, the partial vapour pressure of each component in the solution is
directly proportional to its mole fraction.
For
component 1: P1 α X1
P1 = P10X1
where, P10 = V.P.
of pure component 1.
For
component 2: P2 α X2
P2 = P20X2
where, P20 = V.P.
of pure component 2.
12. The total vapour
pressure (PTotal) over the solution phase in the container is equal
to the sum of partial pressures of the components of the solution. (Dalton’s
Law)
i.e. PTotal = P1 + P2 (where X1 + X2 = 1)
= P10X1 + P20X2
=
P10 + (P20 - P10)X2
13. Colligative
properties:
i) Relative
lowering of vapour pressure:
(PA0 - PA)/
PA0 = XB
= nB/(nA +
nB) {another form of
Raoult’s Law).
OR
(PA0 - PA)/
PA0 = XB
= nB/nA = (wB
x MA)/(MB x wA)
Here
wA & wB are the given mass of component A & B, MA
& MB are the molar mass of component A & B.
ii) Elevation
of Boiling point (∆Tb):
∆Tb = kbm
………(i) { m = (nB x 1000)/wA }
∆Tb = (kb
x wB x 1000)/(MB x wA)
………(ii)
MB = (kb
x wB x 1000)/(∆Tb x wA)
………(iii)
∆Tb = Tb - Tb0
………(iv)
Tb = ∆Tb + Tb0
………(v)
kb = [R x
MA x (Tb0)2]/[1000 x ∆fusH]
………(vi)
where,
∆fusH = enthalpy of fusion
of solvent; MB = Molar mass of solute; wA = Mass
of solvent; wB = Mass of solute; kB = Boiling point
elevation constant (Ebullioscopic constant).
iii) Depression
of Freezing point (∆Tf):
∆Tf = kfm
∆Tf = (kf
x wB x 1000)/(MB x wA)
MB = (kf
x wB x 1000)/(∆Tf x wA)
∆Tf = Tf0 - Tf
Tf = Tf0 + ∆Tf
kf = [R x
MA x (Tf0)2]/[1000 x ∆vapH]
where, R = gas
constant; Tf0 = Freezing point of pure solvent; Tf
= Freezing point of solution;
kf =
Freezing point depression constant or cryoscopic constant; ∆vapH =
enthalpy of vapourisation.
iv) Osmotic
pressure (π):
πV
= nBRT
π
= nBRT/V =
CRT = MRT
(where C = M {Molarity of solution})
π
= (wBRT)/(mB
x V)
14. Van’t
Hoff factor (i):
i = Normal molar mass/Abnormal molar mass
i = Observed colligative property/Calculated
colligative property
i = (Total no. of moles of particles after
association or dissociation)/(No. of moles of particles before association or
dissociation)
15. α = (i - 1)/(n - 1)
where,
α = degree of dissociation; i = Van’t
Hoff factor; n = no. of ions produced
per formula of the compound.
16. α =
[i - 1]/[(1/n)
- 1]
where,
α = degree of association [(1/n) <
1]
17. If i
= 1; Solute behaves normally ( neither association
or dissociation)
i =
½; Solute is dimer
i =
¼; Solute is tetratomic (eg. P4)
i =
1/8; Solute is octa atomic (eg. S8)
i >
1; Solute undergoes dissociation
i <
1; Solute undergoes association
18. Modified
equations for Colligative properties:
(PA0 - PA)/
PA0 = iXB
∆Tb = ikbm
∆Tf = ikfm
π
= inBRT/V
1. Electrical
resistance (R) of electrolytic solution: R
= ρl/A
2. Resistivity (ρ) = RA/l
3. Conductance (G) =
1/R = A/ρl = kA/l
4. Conductivity (κ) = 1/ρ =
l/RA = Gl/A;
(1/R = G)
where,
A = Cross sectional area of cell; l = length of cell
κ
= (l/A) x (1/R) = Cell
constant x Conductance
5. Cell constant of the
conductivity cell
(G*) = l/A =
Conductivity/Conductance
6. κ = Cell
constant/R = G*/R
7. G* = κ x
R
8. Molar conductivity (Ʌm) = κ/C
= 1000 x κ/M
9. Kohlrausch law of independent
migration of ions:
Ʌm0 = ν+λ+0 + ν-λ-0
where, Ʌm0
= limiting molar conductivity; λ+0 and λ-0
are the limiting molar conductivities of cation and anion respectively; ν+
= no. of cations; ν- = no. of anions.
10.
= Ʌmc/Ʌm0
where, Ʌmc
= molar conductivity at concentration ‘C’.
11. ka = Cα2/(1 - α)
ka = Cα2 (α << 1)
where, α = Degree
of dissociation; ka = Dissociation constant of weak acid like acetic
acid.
12. Quantity of electricity passed (Q)
= It
13. Q = nF
where, I =
Current in amperes; t = Time in sec; Q = no. of coulombs required; n = no. of
moles of e-s involved; F = Faraday’s constant = 96,487 Cmol-1
~ 96,500 Cmol-1.
14. Nernst Equation:
Nernst Equation
for the electrode at 298K:
EMn+/M = E0Mn+/M +
(0.059/n)log[Mn+]
Cell potential
for the cell (emf of the cell):
Ecell = E0cell +
(0.059/n)log [reduced form]/[Oxidised form]
where, E0cell
= E0cathode - E0anode
Ecell = E0cell -
(0.059/n)log[products]/[reactants]
15. At Equilibrium, Ecell
= 0,
therefore E0cell =
(0.059/n)log kc
E0cell =
(2.303 RT/nF) log kc
16. ∆rG0 =
-2.303 RT log kc
17. ∆rG0 = -nFEөcell
18. If Ecell is positive, ∆G =
negative; ie cell will work (spontaneously)
If Ecell is negative, ∆G =
positive; ie cell will not work (non-spontaneously)
If Ecell =
0; Cell is at equilibrium.
UNIT 4 : CHEMICAL KINETICS
1. ravg = -
∆[R]/∆t = ∆[P]/∆t
where, ravg
= average rate of reaction
2. rinst =
-d[R]/dt = d[P]/dt
where, rinst
= instantaneous rate of a reaction
3. Rate of
reaction = -(1/νR)d[R]/dt = (1/νP)d[P]/dt
Where vR
and vP are the stoichiometric coefficient of reactant and product,
4. Units for Rate of Reaction =
molL-1s-1
5. Units for rate constant (k) =
(molL-1)1-ns-1
1st order reaction n = 1; k = s-1
2nd order reaction n = 2; k = mol-1Ls-1
0 order reaction n = 0; k = molL-1s-1
6. For a reaction aA + bB + cC -----à Product
Rate = k [A]x[B]y[C]z
Overall order of a reaction = x + y + z. (x, y
and z may same as a, b and c)
7. Integrated rate equation for
zero order reaction:
k = ([R]0 - [R])/t
k = - slope (m = - k)
[R]
= -kt + [R]0
y = mx
+ c
8. Integrated rate equation for first order
reaction:
k
= (1/t) ln [R]0/[R]
k = (2.303/t) log [R]0/[R] OR
= (2.303/t) log(a/a – x)
ln[R] = - kt + ln[R]0
k = - slope
= - m
log [R]0/R = kt/2.303
y
= mx
9. Half-life of a reaction:
a) t1/2 for zero order reaction:
t1/2 = [R]0/2k
t1/2 α R0; t1/2 α 1/k
b) t1/2 for first order reactions:
t1/2 =
0.693/k
First order reaction:
i)t1/2 is independent of [R]
ii) t1/2 α 1/k
9. Arrhenius equation:
k = Ae-Ea/RT
lnk
= -Ea/RT + lnA
lnk1 = -Ea/RT1 + lnA;
at temperature T1
lnk2 = -Ea/RT2 + lnA;
at temperature T2
ln (k2/k1) = Ea/R[(1/T1) - (1/T2)]
log (k2/k1)
= Ea/2.303R[(1/T1) - (1/T2)]
where, t1/2 =
Half Life; [R]0 = Initial concentration of the reactant; [R] =
concentration of the reactant at t; K = Rate constant; Ea =
Activation energy; A = Arhennius factor; T = Absolute temperature; R = Gas
constant.
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By: Mr. S. K. Nigam
PGT Chemistry
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